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(A) The average electric energy density is given by $u_E = \frac{1}{4} \epsilon_0 E_0^2 = \frac{1}{2} \epsilon_0 E_{rms}^2$.The average magnetic energ

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(A) The average electric energy density is given by $u_E = \frac{1}{4} \epsilon_0 E_0^2 = \frac{1}{2} \epsilon_0 E_{rms}^2$.The average magnetic energy density is given by $u_B = \frac{1}{4} \frac{B_0^2}{\mu_0} = \frac{1}{2} \frac{B_{rms}^2}{\mu_0}$.For an electromagnetic wave,the relationship between the amplitudes is $E_0 = c B_0$,where $c = \frac{1}{\sqrt{\mu_0 \epsilon_0}}$.Substituting $E_0 = c B_0$ into the expression for $u_E$:$u_E = \frac{1}{4} \epsilon_0 (c B_0)^2 = \frac{1}{4} \epsilon_0 \left(\frac{1}{\mu_0 \epsilon_0}\right) B_0^2 = \frac{1}{4} \frac{B_0^2}{\mu_0} = u_B$.Therefore,the ratio $\frac{u_E}{u_B} = 1$.

For the plane electromagnetic wave given by $E=E_0 \sin (\omega t-kx)$ and $B=B_0 \sin (\omega t-kx)$,the ratio of average electric energy density to average magnetic energy density is

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