For the reaction,XA + YB rightarrow ZC,if fra | vedclass

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(A) For a general reaction $XA + YB \rightarrow ZC$,the rate of reaction is given by:Rate $= -\frac{1}{X} \frac{d[A]}{dt} = -\frac{1}{Y} \frac{d[B]}{d

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The value of $X = Y = Z = 3$

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(A) For a general reaction $XA + YB ightarrow ZC$,the rate of reaction is given by:Rate $= -\frac{1}{X} \frac{d[A]}{dt} = -\frac{1}{Y} \frac{d[B]}{dt} = \frac{1}{Z} \frac{d[C]}{dt}$Given that $\frac{-d[A]}{dt} = \frac{-d[B]}{dt} = \frac{d[C]}{dt}$,we can equate these to the rate expression:$\frac{1}{X} (	ext{Rate}) = \frac{1}{Y} (	ext{Rate}) = \frac{1}{Z} (	ext{Rate})$This implies that $X = Y = Z$. Since the coefficients in a balanced chemical equation must be equal for the rates of disappearance and appearance to be equal,the simplest integer ratio is $X = Y = Z = 1$. However,looking at the options provided,the statement $X = Y = Z$ is implied by the equality of the rates. Given the options,the most consistent choice is that the coefficients are equal.

For the reaction,$XA + YB \rightarrow ZC$,if $\frac{- d [ A ]}{ dt } = \frac{- d [ B ]}{ dt } = \frac{d [ C ]}{ dt },$ then the correct statement among the following is:

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