For the reaction: Fe_{2}N_{(s)} + frac{3}{2}H | vedclass

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Question

(D) The given reaction is: $Fe_{2}N_{(s)} + \frac{3}{2}H_{2(g)} \rightleftharpoons 2Fe_{(s)} + NH_{3(g)}$The change in the number of gaseous moles is

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$K_{C} = K_{P}(RT)^{1/2}$

Vedclass · Answer

(D) The given reaction is: $Fe_{2}N_{(s)} + \frac{3}{2}H_{2(g)} \rightleftharpoons 2Fe_{(s)} + NH_{3(g)}$The change in the number of gaseous moles is calculated as: $\Delta n_{g} = (n_{products, gas}) - (n_{reactants, gas}) = 1 - \frac{3}{2} = -\frac{1}{2}$The relationship between $K_{P}$ and $K_{C}$ is given by: $K_{P} = K_{C}(RT)^{\Delta n_{g}}$Substituting the value of $\Delta n_{g}$: $K_{P} = K_{C}(RT)^{-1/2}$Rearranging for $K_{C}$: $K_{C} = K_{P}(RT)^{1/2}$

For the reaction: $Fe_{2}N_{(s)} + \frac{3}{2}H_{2(g)} \rightleftharpoons 2Fe_{(s)} + NH_{3(g)}$,which of the following relations is correct?

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