For the reaction 3 A + 2 B rightarrow C,which | vedclass

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(C) For the reaction $3 A + 2 B \rightarrow C$,the rate of reaction is expressed as:
$-\frac{1}{3} \frac{d[A]}{dt} = -\frac{1}{2} \frac{d[B]}{dt} = \

Vedclass · Accepted Answer

Rate of disappearance of $A$ is $3/2$ times of rate of disappearance of $B$

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(C) For the reaction $3 A + 2 B \rightarrow C$,the rate of reaction is expressed as:
$-\frac{1}{3} \frac{d[A]}{dt} = -\frac{1}{2} \frac{d[B]}{dt} = \frac{d[C]}{dt}$
Here,$-\frac{d[A]}{dt}$ is the rate of disappearance of $A$,$-\frac{d[B]}{dt}$ is the rate of disappearance of $B$,and $\frac{d[C]}{dt}$ is the rate of formation of $C$.
From the relation $-\frac{1}{3} \frac{d[A]}{dt} = -\frac{1}{2} \frac{d[B]}{dt}$,we get:
$-\frac{d[A]}{dt} = \frac{3}{2} \left( -\frac{d[B]}{dt} \right)$.
This means the rate of disappearance of $A$ is $3/2$ times the rate of disappearance of $B$.

For the reaction $3 A + 2 B \rightarrow C$,which statement is correct $:-$

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