Difficult
For the reaction between $A$ and $B$,the initial rate of reaction $(r_0)$ was measured for different initial concentrations of $A$ and $B$ as given below. Determine the order of the reaction with respect to $A$ and $B$ respectively.
$[A] / mol \ L^{-1}$ $0.2, 0.2, 0.4$ $[B] / mol \ L^{-1}$ $0.3, 0.1, 0.05$ $r_0 / mol \ L^{-1} s^{-1}$ $5.0 \times 10^{-5}, 5.0 \times 10^{-5}, 1.4 \times 10^{-4}$
| $[A] / mol \ L^{-1}$ | $0.2, 0.2, 0.4$ |
| $[B] / mol \ L^{-1}$ | $0.3, 0.1, 0.05$ |
| $r_0 / mol \ L^{-1} s^{-1}$ | $5.0 \times 10^{-5}, 5.0 \times 10^{-5}, 1.4 \times 10^{-4}$ |
- A$\frac{1}{2}, 0$
- B$\frac{3}{2}, \frac{1}{3}$
- C$\frac{3}{2}, 0$
- D$0, \frac{5}{2}$
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Consider the reaction $2 \ A + 2 \ B \rightarrow C + 2 \ D$. If the concentration of $A$ is doubled at constant $B$,the rate increases by a factor of $4$. If the concentration of $B$ is doubled at constant $A$,the rate is doubled. What is the rate law?
The reaction between $A$ and $B$ is first order with respect to $A$ and zero order with respect to $B$. Fill in the blanks in the following table:
Experiment $[A] / mol \, L^{-1}$ $[B] / mol \, L^{-1}$ Initial rate / $mol \, L^{-1} \, min^{-1}$ $I$ $0.1$ $0.1$ $2.0 \times 10^{-2}$ $II$ $-$ $0.2$ $4.0 \times 10^{-2}$ $III$ $0.4$ $0.4$ $-$ $IV$ $-$ $0.2$ $2.0 \times 10^{-2}$
| Experiment | $[A] / mol \, L^{-1}$ | $[B] / mol \, L^{-1}$ | Initial rate / $mol \, L^{-1} \, min^{-1}$ |
|---|---|---|---|
| $I$ | $0.1$ | $0.1$ | $2.0 \times 10^{-2}$ |
| $II$ | $-$ | $0.2$ | $4.0 \times 10^{-2}$ |
| $III$ | $0.4$ | $0.4$ | $-$ |
| $IV$ | $-$ | $0.2$ | $2.0 \times 10^{-2}$ |
Difficult
View SolutionIf the concentration of reactant $B$ is doubled,the rate of the reaction between reactants $A$ and $B$ becomes $1/4$ of the initial rate. The order of the reaction with respect to reactant $B$ is ......
Medium
View SolutionFor the reaction $2A + B \rightarrow C + D$,select the correct rate law based on the following data:
$1$. $[A] = 0.1, [B] = 0.1, \text{Initial Rate} = 7.5 \times 10^{-3}$
$2$. $[A] = 0.3, [B] = 0.2, \text{Initial Rate} = 9.0 \times 10^{-2}$
$3$. $[A] = 0.3, [B] = 0.4, \text{Initial Rate} = 3.6 \times 10^{-1}$
$4$. $[A] = 0.4, [B] = 0.1, \text{Initial Rate} = 3.0 \times 10^{-2}$
$1$. $[A] = 0.1, [B] = 0.1, \text{Initial Rate} = 7.5 \times 10^{-3}$
$2$. $[A] = 0.3, [B] = 0.2, \text{Initial Rate} = 9.0 \times 10^{-2}$
$3$. $[A] = 0.3, [B] = 0.4, \text{Initial Rate} = 3.6 \times 10^{-1}$
$4$. $[A] = 0.4, [B] = 0.1, \text{Initial Rate} = 3.0 \times 10^{-2}$
Easy
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