For the reaction given below:The compound whi | vedclass

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(C) The given reaction is an intramolecular Cannizzaro reaction because the substrate $4-formylbenzyl alcohol$ contains both an aldehyde group $(-CHO)

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dicarboxylic acid

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(C) The given reaction is an intramolecular Cannizzaro reaction because the substrate $4-formylbenzyl alcohol$ contains both an aldehyde group $(-CHO)$ and a hydroxymethyl group $(-CH_2OH)$,but no $\alpha$-hydrogen atoms.In the presence of concentrated $NaOH$ and heat,the aldehyde group undergoes disproportionation (oxidation and reduction).The oxidation of the $-CHO$ group leads to the formation of a carboxylic acid group $(-COOH)$,while the reduction of the $-CHO$ group leads to the formation of a primary alcohol group $(-CH_2OH)$.The final products are $1,4-benzenedimethanol$ (a diol) and $4-(hydroxymethyl)benzoic acid$ (a compound with both alcohol and acid functional groups).Comparing these products with the options:$A$. Compound with both alcohol and acid functional groups: Formed $(4-(hydroxymethyl)benzoic acid)$.$B$. Monocarboxylic acid: Formed ($4-(hydroxymethyl)benzoic acid$ is a monocarboxylic acid).$C$. Dicarboxylic acid: Not formed.$D$. Diol: Formed ($1,4-benzenedimethanol$ is a diol).Therefore,the compound that is not formed is a dicarboxylic acid.

For the reaction given below:
The compound which is not formed as a product in the reaction is a:

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For the reaction given below:The compound which is not formed as a product in the reaction is a: