For the reaction given below:CoCl_{3} cdot xN | vedclass

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(C) The reaction of coordination compounds with $AgNO_{3}$ depends on the number of chloride ions present outside the coordination sphere (ionizable c

Vedclass · Accepted Answer

$5$

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(C) The reaction of coordination compounds with $AgNO_{3}$ depends on the number of chloride ions present outside the coordination sphere (ionizable chlorides).The reaction is given by: $[Co(NH_{3})_{x}Cl_{3-n}]Cl_{n} + nAgNO_{3} \rightarrow nAgCl \downarrow + [Co(NH_{3})_{x}Cl_{3-n}](NO_{3})_{n}$.Given that $2$ equivalents of $AgCl$ precipitate,it implies that there are $2$ ionizable chloride ions $(n = 2)$.Thus,the complex is $[Co(NH_{3})_{5}Cl]Cl_{2}$.Comparing this with the formula $CoCl_{3} \cdot xNH_{3}$,we find that $x = 5$.

For the reaction given below:
$CoCl_{3} \cdot xNH_{3} + AgNO_{3(aq)} \rightarrow$
If two equivalents of $AgCl$ precipitate out,then the value of $x$ will be $....$

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For the reaction given below:$CoCl_{3} \cdot xNH_{3} + AgNO_{3(aq)} \rightarrow$If two equivalents of $AgCl$ precipitate out,then the value of $x$ will be $....$