For the reaction sequence: $P$ $\xrightarrow[2. H_3O^+]{1. CH_3MgBr} R$ $\xrightarrow[2. \Delta]{1. \text{dil. } NaOH} \text{4-methylpent-3-en-2-one}$,identify $P$.
- AEthanamine
- BEthanal
- CPropanone
- DEthanenitrile
Explore More
Similar Questions
$H_2 + CO +$ alkene $\xrightarrow{\text{catalyst}} 1^\circ$ alcohol. What is the stable intermediate and the nature of the reaction?
Match List-$I$ with List-$II$.
$A$. $C_6H_5COCl + H_2 \xrightarrow{Pd-BaSO_4} C_6H_5CHO$ $I$. Gattermann-Koch reaction $B$. $CH_3CN + SnCl_2 + HCl \rightarrow CH_3CHO$ $II$. Etard reaction $C$. $C_6H_5CH_3 + CrO_2Cl_2 \rightarrow C_6H_5CHO$ $III$. Stephen reaction $D$. $C_6H_6 + CO + HCl \xrightarrow{AlCl_3} C_6H_5CHO$ $IV$. Rosenmund reaction
Choose the correct answer from the options given below.
| $A$. $C_6H_5COCl + H_2 \xrightarrow{Pd-BaSO_4} C_6H_5CHO$ | $I$. Gattermann-Koch reaction |
| $B$. $CH_3CN + SnCl_2 + HCl \rightarrow CH_3CHO$ | $II$. Etard reaction |
| $C$. $C_6H_5CH_3 + CrO_2Cl_2 \rightarrow C_6H_5CHO$ | $III$. Stephen reaction |
| $D$. $C_6H_6 + CO + HCl \xrightarrow{AlCl_3} C_6H_5CHO$ | $IV$. Rosenmund reaction |
Choose the correct answer from the options given below.
DifficultJEE MAIN 2022
View SolutionThe oxidation of benzyl chloride with lead nitrate gives
Medium
View SolutionThe product $(B)$ of the following reaction is:
Medium
View Solution$CH_3COCl \xrightarrow{Pd/BaSO_4, H_2} CH_3CHO + HCl$
The above reaction is called:
The above reaction is called:
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo