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(B) The graph shows a linear plot of $[AB]$ versus $time$, which indicates a zero-order reaction.For a zero-order reaction, the rate law is $[AB]_0 -

Vedclass · Accepted Answer

$10$

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(B) The graph shows a linear plot of $[AB]$ versus $time$, which indicates a zero-order reaction.For a zero-order reaction, the rate law is $[AB]_0 - [AB]_t = kt$.From the graph, at $t = 0 \ s$, $[AB]_0 = 0.6 \ M$.At $t = 100 \ s$, $[AB]_t = 0.55 \ M$.Substituting these values: $0.6 - 0.55 = k(100) \implies 0.05 = 100k \implies k = 5 	imes 10^{-4} \ M \ s^{-1}$.The half-life for a zero-order reaction is given by $t_{1/2} = \frac{[AB]_0}{2k}$.$t_{1/2} = \frac{0.6}{2 	imes 5 	imes 10^{-4}} = \frac{0.6}{10^{-3}} = 600 \ s$.Converting to minutes: $t_{1/2} = \frac{600}{60} = 10 \ min$.Therefore, $x = 10$.

For the thermal decomposition of reaction $AB_{(g)}$, the following graph is provided. The half-life of the reaction is $x \ min$. Find $x$. (Nearest integer)

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