For the wavelength of visible radiation of the hydrogen spectrum,Balmer gave an equation as $\lambda = \frac{(k m^2)}{(m^2 - 4)}$,where $m$ is an integer. The value of $k$ in terms of Rydberg's constant $R$ is

  • A
    $\frac{R}{4}$
  • B
    $\frac{4}{R}$
  • C
    $R$
  • D
    $4 R$

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Similar Questions

The ratio of wavelengths of the second line in the Balmer series and the first line in the Lyman series of a hydrogen atom is:

The longest wavelength associated with the Paschen series is: (Given $R_H = 1.097 \times 10^7 \ m^{-1}$)

Let the series limit for the Balmer series be $\lambda_{1}$ and the longest wavelength for the Brackett series be $\lambda_{2}$. Then $\lambda_{1}$ and $\lambda_{2}$ are related as:

In the hydrogen spectrum,the wavelengths of light emitted in a series of spectral lines is given by the equation,$\frac{1}{\lambda}=R\left(\frac{1}{4^{2}}-\frac{1}{n^{2}}\right)$,where $n=5, 6, 7, \ldots$ and $R$ is Rydberg's constant. Identify the series and wavelength region.

The ratio of wavelengths of the last line of the Balmer series and the last line of the Lyman series is

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