For what value of x is the statement left(fra | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Given the equation: $\left(\frac{x}{15}ight)\left(\frac{x}{135}ight) = 1$Multiply the numerators and denominators: $\frac{x^2}{15 	imes 135}

Vedclass · Accepted Answer

$45$

Vedclass · Answer

(D) Given the equation: $\left(\frac{x}{15}ight)\left(\frac{x}{135}ight) = 1$Multiply the numerators and denominators: $\frac{x^2}{15 	imes 135} = 1$$x^2 = 15 	imes 135$$x^2 = 15 	imes (15 	imes 9)$$x^2 = 15^2 	imes 3^2$Taking the square root on both sides: $x = \sqrt{15^2 	imes 3^2}$$x = 15 	imes 3 = 45$Therefore,the value of $x$ is $45$.

For what value of $x$ is the statement $\left(\frac{x}{15}\right)\left(\frac{x}{135}\right)=1$ true?

Similar Questions

If $3 \sqrt{5}+\sqrt{125}=17.88$,then what will be the value of $\sqrt{80}+6 \sqrt{5}$?

If $\sqrt{2} = 1.414$,the square root of $\frac{\sqrt{2}-1}{\sqrt{2}+1}$ is nearest to

$\sqrt{0.00004761} = ?$

$(2 \sqrt{392}-21)+(\sqrt{8}-7)^{2}=(?)^{2}$

$\sqrt{54} \times \sqrt{2120} \div \sqrt{460} = ?$

Vedclass Test Series

Exam Paper Generator

Online Exam Module