For which of the following particles will it | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The de Broglie wavelength is given by $\lambda = \frac{h}{mv}$.For a particle to exhibit wave-like properties,its wavelength $\lambda$ must be lar

Vedclass · Accepted Answer

a dust particle

Vedclass · Answer

(D) The de Broglie wavelength is given by $\lambda = \frac{h}{mv}$.For a particle to exhibit wave-like properties,its wavelength $\lambda$ must be large enough to be detected experimentally.Since $\lambda$ is inversely proportional to the mass $m$ of the particle,particles with very large masses have extremely small wavelengths that are impossible to measure with current technology.Among the given options,a dust particle has the largest mass ($m$ is very high).Therefore,the de Broglie wavelength for a dust particle is extremely small,making it the most difficult to experimentally verify.

For which of the following particles will it be most difficult to experimentally verify the de Broglie relationship?

Similar Questions

The kinetic energy of an electron is increased by $2$ times,then the de-Broglie wavelength associated with it changes by a factor.

The ratio of the de-Broglie wavelength of an $\alpha$-particle and a proton accelerated from rest by the same potential is $\frac{1}{\sqrt{m}}$. The value of $m$ is $........$

An electron is accelerated through a potential difference of $10,000 \; V$. Its de Broglie wavelength is,(nearly):
$(m_{e}=9 \times 10^{-31} \; kg)$

If the de Broglie wavelength of an electron is $5200 \ \mathring{A}$,what is its velocity?

An electron of mass $m$ with an initial velocity $\vec{V} = V_0 \hat{i} \,(V_0 > 0)$ enters an electric field $\vec{E} = -E_0 \hat{i} \,(E_0 = \text{constant} > 0)$ at $t = 0$. If $\lambda_0$ is its de-Broglie wavelength initially,then its de-Broglie wavelength at time $t$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module