For which of the following processes,Delta S | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) . The conversion of diamond to graphite involves a structural change where entropy generally increases,so $\Delta S > 0$.$B$. When the pressure of

Vedclass · Accepted Answer

$N_2(g, 1 \ atm) 	o N_2(g, 5 \ atm)$

Vedclass · Answer

(B) . The conversion of diamond to graphite involves a structural change where entropy generally increases,so $\Delta S > 0$.$B$. When the pressure of a gas increases at constant temperature,the gas molecules are compressed into a smaller volume,leading to a decrease in the number of available microstates and a decrease in randomness. Thus,$\Delta S $C$. Increasing the temperature of a gas increases the kinetic energy and the randomness of the molecules,leading to an increase in entropy,so $\Delta S > 0$.$D$. The dissociation of $H_2$ gas into $2H$ atoms increases the number of moles of gas particles,which increases the disorder of the system,so $\Delta S > 0$.

For which of the following processes,$\Delta S$ is negative?

Similar Questions

When a solid is converted into liquid,entropy

Why does the entropy of a substance increase with an increase in temperature?

Enthalpy of vaporization of benzene is $+35.3 \ kJ \ mol^{-1}$ at its boiling point,$80^{\circ} C$. The entropy change in the transition of the vapour to liquid at its boiling point in $[J \ K^{-1} \ mol^{-1}]$ is

What is the unit of entropy?

Which one of the following involves a decrease in entropy?

Vedclass Test Series

Exam Paper Generator

Online Exam Module