For which of the following transition metal i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The magnetic moment $(\mu)$ is calculated using the formula $\mu = \sqrt{n(n+2)} 	ext{ B.M.}$,where $n$ is the number of unpaired electrons.For $

Vedclass · Accepted Answer

$3d^5$

Vedclass · Answer

(C) The magnetic moment $(\mu)$ is calculated using the formula $\mu = \sqrt{n(n+2)} 	ext{ B.M.}$,where $n$ is the number of unpaired electrons.For $3d^1$,$n = 1$,$\mu = \sqrt{1(3)} = 1.73 	ext{ B.M.}$For $3d^8$,$n = 2$,$\mu = \sqrt{2(4)} = 2.83 	ext{ B.M.}$For $3d^5$,$n = 5$,$\mu = \sqrt{5(7)} = 5.92 	ext{ B.M.}$For $3d^7$,$n = 3$,$\mu = \sqrt{3(5)} = 3.87 	ext{ B.M.}$Thus,the $3d^5$ configuration has the highest number of unpaired electrons $(n=5)$,resulting in the highest magnetic moment.

For which of the following transition metal ion configurations is the highest magnetic moment observed?

Similar Questions

The $3d-$ elements show variable oxidation states. What is the maximum oxidation state shown by the element $Mn$?

Which of the following species is expected to show the highest magnetic moment? (At. Nos.: $Cr = 24$,$Mn = 25$,$Co = 27$,$Ni = 28$,$Cu = 29$)

Which of the following elements exhibits ferromagnetic properties?

Besides $Zn$ and $Cu$,german silver contains the metal

Identify the correct decreasing order of densities of $d-$block elements.

Vedclass Test Series

Exam Paper Generator

Online Exam Module