The force F acting on a particle moving in a | vedclass

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(B) The work done by a variable force is equal to the area under the force-displacement $(F-d)$ graph.The graph consists of a rectangle from $d = 3\,

Vedclass · Accepted Answer

$13$

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(B) The work done by a variable force is equal to the area under the force-displacement $(F-d)$ graph.The graph consists of a rectangle from $d = 3\, m$ to $d = 7\, m$ and a triangle from $d = 7\, m$ to $d = 12\, m$.Area of the rectangle = $	ext{width} 	imes 	ext{height} = (7 - 3) 	imes 2 = 4 	imes 2 = 8\, J$.Area of the triangle = $\frac{1}{2} 	imes 	ext{base} 	imes 	ext{height} = \frac{1}{2} 	imes (12 - 7) 	imes 2 = \frac{1}{2} 	imes 5 	imes 2 = 5\, J$.Total work done = $	ext{Area of rectangle} + 	ext{Area of triangle} = 8 + 5 = 13\, J$.

The force $F$ acting on a particle moving in a straight line varies with distance $d$ as shown in the figure. The work done on the particle during its displacement of $12\, m$ is ................. $J$.

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