The force required to move a mass of 1, kg at | vedclass

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(A) To move an object from rest on a horizontal rough surface, the applied force $F$ must be at least equal to the maximum static frictional force $f_

Vedclass · Accepted Answer

$0.98$

Vedclass · Answer

(A) To move an object from rest on a horizontal rough surface, the applied force $F$ must be at least equal to the maximum static frictional force $f_{s,max}$.The formula for the maximum static frictional force is $f_{s,max} = \mu_s N$, where $\mu_s$ is the coefficient of static friction and $N$ is the normal force.For a horizontal surface, the normal force $N$ is equal to the weight of the object, $N = mg$.Given:Mass $m = 1\, kg$Coefficient of friction $\mu = 0.1$Acceleration due to gravity $g = 9.8\, m/s^2$Substituting the values:$N = mg = 1 	imes 9.8 = 9.8\, N$$F = f_{s,max} = \mu N = 0.1 	imes 9.8 = 0.98\, N$Therefore, the force required to move the mass is $0.98\, N$.

The force required to move a mass of $1\, kg$ at rest on a horizontal rough plane ($\mu = 0.1$ and $g = 9.8\, m/s^2$) is ........ $N$.

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