(C) . In Cannizzaro reaction,an aldehyde lacking $\alpha$-hydrogen undergoes self-oxidation and reduction (disproportionation) in the presence of a co

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(C) . In Cannizzaro reaction,an aldehyde lacking $\alpha$-hydrogen undergoes self-oxidation and reduction (disproportionation) in the presence of a concentrated base.$2HCHO + KOH \xrightarrow{\text{conc.}} CH_3OH + HCOOK$Here,one molecule of formaldehyde is reduced to methanol $(CH_3OH)$ and another is oxidized to potassium formate $(HCOOK)$.

Class 12 Chemistry 8-1.Aldehydes and Ketones Properties

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Formaldehyde when treated with $KOH$ gives methanol and potassium formate. The reaction is known as

A
Perkin reaction
B
Claisen reaction
C
Cannizzaro reaction
D
Knoevenagel reaction

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Formaldehyde when treated with $KOH$ gives methanol and potassium formate. The reaction is known as

Similar Questions

Methyl vinyl ketone on reaction with $LiCuMe_2$ gives a major product,whose structure is

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$CH_{3}CH_{2}CN$ $\xrightarrow[Ether]{CH_{3}MgBr} A$ $\xrightarrow{H_{3}O^{+}} B$ $\xrightarrow[HCl]{Zn-Hg} C$The correct structure of $C$ is

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$CH_{3}CH_{2}CN$ $\xrightarrow[Ether]{CH_{3}MgBr} A$ $\xrightarrow{H_{3}O^{+}} B$ $\xrightarrow[HCl]{Zn-Hg} C$
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Identify product $B$ in the following sequence of reactions:
$2 \ CH_3COCH_3$ $\xrightarrow{Ba(OH)_2} A$ $\xrightarrow{\Delta, -H_2O} B$