Formic acid can reduce

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(D) Formic acid $(HCOOH)$ acts as both a carboxylic acid and an aldehyde due to the presence of the aldehydic group $(-CHO)$ in its structure.$(A)$ To

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All of these

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(D) Formic acid $(HCOOH)$ acts as both a carboxylic acid and an aldehyde due to the presence of the aldehydic group $(-CHO)$ in its structure.$(A)$ Tollen's reagent: $HCOOH + Ag_2O 	o CO_2 + H_2O + 2Ag$ (Silver mirror is formed).$(B)$ Mercuric chloride: $HCOOH + 2HgCl_2 	o 2CO_2 + 4HCl + 2Hg$ (Black precipitate of $Hg$ is formed).$(C)$ $KMnO_4$: $5HCOOH + 2KMnO_4 + 3H_2SO_4 	o 5CO_2 + K_2SO_4 + 2MnSO_4 + 8H_2O$ (Decolorization of $KMnO_4$ occurs).Since formic acid reduces all of these,the correct option is $(D)$.

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