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(A) By analyzing the circuit diagram,we can see that all four capacitors are connected in parallel between points $A$ and $B$.Since each capacitor has

Vedclass · Accepted Answer

$32$

Vedclass · Answer

(A) By analyzing the circuit diagram,we can see that all four capacitors are connected in parallel between points $A$ and $B$.Since each capacitor has a capacitance of $C = 8\,\mu F$,and they are in parallel,the equivalent capacitance $C_{eq}$ is given by the sum of individual capacitances:$C_{eq} = C_1 + C_2 + C_3 + C_4$$C_{eq} = 8\,\mu F + 8\,\mu F + 8\,\mu F + 8\,\mu F = 32\,\mu F$.Thus,the equivalent capacitance between points $A$ and $B$ is $32\,\mu F$.

Four capacitors are connected as shown in the adjoining figure. The capacitance of each is $8\,\mu F$. The equivalent capacitance between the points $A$ and $B$ will be......$\mu F$.

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