Four-digit numbers are formed using the digits $1, 2, 3, 4$ (repetition is allowed). The number of such four-digit numbers divisible by $11$ is

  • A
    $22$
  • B
    $36$
  • C
    $44$
  • D
    $52$

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Similar Questions

The number $(49^{2}-4)(49^{3}-49)$ is divisible by (in $!$)

Five-digit numbers are formed using the digits $1, 2, 3, 4, 5, 6$,and $8$. What is the probability that they have even digits at both the ends?

$A$ man $P$ has $7$ friends,$4$ of them are ladies and $3$ are men. His wife $Q$ also has $7$ friends,$3$ of them are ladies and $4$ are men. Assume $P$ and $Q$ have no common friends. Then the total number of ways in which $P$ and $Q$ together can throw a party inviting $3$ ladies and $3$ men,so that $3$ friends of each of $P$ and $Q$ are in this party,is . . . . . . .

Consider the following statements:
$(i)$ The number of one-one functions from set $A$ to set $B$,where $O(A) = m$ and $O(B) = n$ $(m \leq n)$,is given by ${}^n P_m$.
(ii) The number of ways in which $n$ people can be arranged at a circular table is $\frac{(n-1)!}{2}$.
(iii) The number of ways of selecting at least one thing out of the given $n$ distinct things is $2^n - 1$.
(iv) The number of ways in which $n$ distinguishable objects can be distributed into $k$ distinguishable bins is ${}^n C_{k-1}$.
Which of the following is true?

Match the items of List-$I$ to the items of List-$II$:
List-$I$ List-$II$
$(A)$ The number of ways of not selecting $(n-r)$ things from $n$ different things $(I)$ $1+n+{ }^n C_2+\ldots+{ }^n C_r$
$(B)$ $(n-r+1) \cdot{ }^n C_{r-1}$ $(II)$ $(r+1) \cdot{ }^n C_{r+1}$
$(C)$ The number of ways of selecting at least $(n-r)$ things from $n$ different things $(III)$ $r\left({ }^n C_r\right)$
$(D)$ $(n-r)\left({ }^{n-1} C_{r-1}+{ }^{n-1} C_r\right)$ $(IV)$ $2^n-1-n-{ }^n C_2-\ldots-{ }^n C_r$
$(V)$ ${ }^n C_{n-r}$

The correct match is:

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