Four gases A,B,C,and D have critical temperat | vedclass

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Question

(D) The extent of adsorption of a gas on a solid adsorbent like charcoal is directly proportional to its critical temperature $(T_c)$.Higher critical

Vedclass · Accepted Answer

$D > C > B > A$

Vedclass · Answer

(D) The extent of adsorption of a gas on a solid adsorbent like charcoal is directly proportional to its critical temperature $(T_c)$.Higher critical temperature implies that the gas is more easily liquefiable and has stronger van der Waals forces of attraction.Given critical temperatures are:$A = 5.3 \ K$$B = 33.2 \ K$$C = 126.0 \ K$$D = 154.3 \ K$Therefore,the order of adsorption is $D > C > B > A$.

Four gases $A$,$B$,$C$,and $D$ have critical temperatures $5.3 \ K$,$33.2 \ K$,$126.0 \ K$,and $154.3 \ K$ respectively. For their adsorption on a fixed amount of charcoal,the correct order is:

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