Four plates of equal area $A$ are separated by equal distances $d$ and are arranged as shown in the figure. The equivalent capacity is

Two capacitors $C_1 = 3 \mu F$ and $C_2 = 2 \mu F$ are connected in series across a d.c. source of $100 \ V$. The ratio of the potential across $C_2$ to $C_1$ is

The equivalent capacitance of three capacitors of capacitance $C_1, C_2$ and $C_3$ connected in parallel is $12$ units and their product is $C_1 \cdot C_2 \cdot C_3 = 48$. When the capacitors $C_1$ and $C_2$ are connected in parallel,the equivalent capacitance is $6$ units. Then the capacitances are:

Find the equivalent capacitance between two points $A$ and $B$ for the given circuit. (Capacitance of each capacitor is $C = 3 \mu F$.) (in $\mu F$)

The equivalent capacitance between terminals $A$ and $B$ is:

What is the equivalent capacitance between $A$ and $B$ in the given figure (all values are in farad)?