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(B) The charges are placed on the circumference of a circle of diameter $2d$. The radius of the circle is $r = 	ext{Diameter} / 2 = (2d) / 2 = d$.Sin

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$q/d$

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(B) The charges are placed on the circumference of a circle of diameter $2d$. The radius of the circle is $r = 	ext{Diameter} / 2 = (2d) / 2 = d$.Since the charges form a square inscribed in the circle,each charge is at a distance $r = d$ from the center.The electric potential $V$ at the center due to a single point charge $q$ at distance $r$ is given by $V = \frac{1}{4 \pi \varepsilon_0} \frac{q}{r}$.Since there are four identical charges,the total potential $V_{total}$ at the center is the sum of the potentials due to each charge:$V_{total} = \frac{1}{4 \pi \varepsilon_0} \left( \frac{q}{d} + \frac{q}{d} + \frac{q}{d} + \frac{q}{d} ight)$$V_{total} = \frac{1}{4 \pi \varepsilon_0} \left( \frac{4q}{d} ight) = \frac{q}{\pi \varepsilon_0 d}$.Thus,the potential at the center is proportional to $q/d$.

Four point charges each $+q$ are placed on the circumference of a circle of diameter $2d$ in such a way that they form a square. The potential at the centre is proportional to

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