Four wires each of length 2.0 , m are bent in | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The torque $	au$ acting on a current-carrying loop in a uniform magnetic field is given by $	au = |\vec{m} 	imes \vec{B}| = mB \sin 	heta$,whe

Vedclass · Accepted Answer

Torque on loop $S$ will be the highest.

Vedclass · Answer

(D) The torque $	au$ acting on a current-carrying loop in a uniform magnetic field is given by $	au = |\vec{m} 	imes \vec{B}| = mB \sin 	heta$,where $m = iA$ is the magnetic moment.Since the current $i$ and the magnetic field $B$ are the same for all loops,the torque is directly proportional to the area $A$ of the loop $(	au \propto A)$.For a fixed perimeter (length of wire),the area enclosed by a geometric shape is maximum for a circle.Among the given shapes (rectangles and a circle),the circular loop $S$ has the maximum area for the same perimeter of $2.0 \, m$.Therefore,the magnetic moment $m = iA$ and the resulting torque $	au$ will be maximum for loop $S$.

Four wires each of length $2.0 \, m$ are bent into four loops $P$,$Q$,$R$ (labeled as $P$ in the image,but distinct),and $S$ and then suspended in a uniform magnetic field. The same current is passed through each loop. Which statement is correct?

Similar Questions

$A$ current-carrying loop is placed in a uniform magnetic field in four different orientations,$I$,$II$,$III$,and $IV$. Arrange them in the decreasing order of potential energy.

Two wires of equal lengths are bent in the form of a square and a circular loop. They are suspended in a uniform magnetic field and the same current is passed through them. The torque experienced by:

Vedclass Test Series

Exam Paper Generator

Online Exam Module