Four years ago,the father's age was three tim | vedclass

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(D) Let the present ages of the father and the son be $f$ and $s$ respectively.From the given information:$1$. Four years ago: $(f - 4) = 3(s - 4) \Ri

Vedclass · Accepted Answer

$40$

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(D) Let the present ages of the father and the son be $f$ and $s$ respectively.From the given information:$1$. Four years ago: $(f - 4) = 3(s - 4) \Rightarrow f - 4 = 3s - 12 \Rightarrow f - 3s = -8$ ... $(i)$$2$. After four years: $(f + 4) + (s + 4) = 64 \Rightarrow f + s + 8 = 64 \Rightarrow f + s = 56$ ... (ii)From equation (ii),$s = 56 - f$. Substituting this into equation $(i)$:$f - 3(56 - f) = -8$$f - 168 + 3f = -8$$4f = 160$$f = 40$Thus,the father's present age is $40$ years.

Four years ago,the father's age was three times the age of his son. The total of the ages of the father and the son after four years will be $64$ years. What is the father's age at present (in years)?

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