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(C) Total number of cards in a pack $= 52$.Number of kings in a pack $= 4$.Number of queens in a pack $= 4$.Since the cards are drawn one by one witho

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$\frac{4}{663}$

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(C) Total number of cards in a pack $= 52$.Number of kings in a pack $= 4$.Number of queens in a pack $= 4$.Since the cards are drawn one by one without replacement:Probability of drawing a king first $= P(K_1) = \frac{4}{52} = \frac{1}{13}$.After drawing one king,the remaining number of cards is $51$.Probability of drawing a queen second given that the first was a king $= P(Q_2|K_1) = \frac{4}{51}$.Required probability $= P(K_1) 	imes P(Q_2|K_1) = \frac{4}{52} 	imes \frac{4}{51} = \frac{1}{13} 	imes \frac{4}{51} = \frac{4}{663}$.

From a pack of $52$ cards,two cards are drawn one by one without replacement. The probability that the first drawn card is a king and the second is a queen,is

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