From out of 100 enrolled students,two section | vedclass

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Question

(B) Total number of ways to select $2$ students out of $100$ is ${ }^{100} C_2$. Number of ways in which both you and your friend are placed in the fi

Vedclass · Accepted Answer

$\frac{{ }^{40} C_2+{ }^{60} C_2}{{ }^{100} C_2}$

Vedclass · Answer

(B) Total number of ways to select $2$ students out of $100$ is ${ }^{100} C_2$. Number of ways in which both you and your friend are placed in the first section (strength $40$) is ${ }^{40} C_2$. Number of ways in which both you and your friend are placed in the second section (strength $60$) is ${ }^{60} C_2$. Since these are mutually exclusive events,the total number of favorable ways is ${ }^{40} C_2 + { }^{60} C_2$. Therefore,the required probability is $\frac{{ }^{40} C_2 + { }^{60} C_2}{{ }^{100} C_2}$.

From out of $100$ enrolled students,two sections of strength $40$ and $60$ are formed. If you and your friend are among those $100$ students,then the probability that both of you are placed in the same section is

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