From the given reaction,$N_{2(g)} + 3H_{2(g)} \longrightarrow 2NH_{3(g)} \quad \Delta H = -92.6 \ kJ$,the enthalpy of formation of $NH_3$ is (in $kJ$):

  • A
    $-92.6$
  • B
    $-138.9$
  • C
    $-185.2$
  • D
    $-46.3$

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