The general configuration of the outermost an | vedclass

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(C) Given the configuration: $(n - 1)s^2 (n - 1)p^6 (n - 1)d^x ns^2$. For $n = 4$ and $x = 5$,the configuration becomes $3s^2 3p^6 3d^5 4s^2$. This co

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$25$

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(C) Given the configuration: $(n - 1)s^2 (n - 1)p^6 (n - 1)d^x ns^2$. For $n = 4$ and $x = 5$,the configuration becomes $3s^2 3p^6 3d^5 4s^2$. This corresponds to the element Manganese $(Mn)$,which has an atomic number of $25$. The total number of electrons is calculated by summing the electrons in all shells: $1s^2 2s^2 2p^6 3s^2 3p^6 3d^5 4s^2$. Total electrons $= 2 + 2 + 6 + 2 + 6 + 5 + 2 = 25$. Since the number of protons equals the number of electrons in a neutral atom,the number of protons is $25$.

The general configuration of the outermost and penultimate shell is $(n - 1)s^2 (n - 1)p^6 (n - 1)d^x ns^2$. If $n = 4$ and $x = 5$,then the number of protons in the nucleus will be:

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