Give the conversion of the following:
$(i)$ Benzoic acid from Bromobenzene
(ii) $2$-methylbutan-$2$-ol from Propenone

(N/A) $(i)$ Conversion of Bromobenzene to Benzoic acid:
$1$. Bromobenzene reacts with $Mg$ in the presence of dry ether to form Phenylmagnesium bromide $(C_6H_5MgBr)$.
$2$. $C_6H_5MgBr$ reacts with $CO_2$ followed by acidic hydrolysis to form Benzoic acid $(C_6H_5COOH)$.
(ii) Conversion of Propenone (Acetone) to $2$-methylbutan-$2$-ol:
$1$. Propenone $(CH_3COCH_3)$ reacts with Ethylmagnesium bromide $(CH_3CH_2MgBr)$ in the presence of dry ether.
$2$. This forms an addition product which,upon acidic hydrolysis,yields $2$-methylbutan-$2$-ol $(CH_3CH_2C(OH)(CH_3)_2)$.