Provide the chemical conversion for the following:
$(i)$ $3-$phenylprop$-2-$enal from Benzaldehyde and Ethanal (Cross-Aldol Condensation).
$(ii)$ Benzyl alcohol from Benzene.

(N/A) $(i)$ $3-$phenylprop$-2-$enal is prepared by the cross-aldol condensation of Benzaldehyde $(C_6H_5CHO)$ and Ethanal $(CH_3CHO)$ in the presence of dilute $NaOH$ followed by dehydration.
$C_6H_5CHO + CH_3CHO$ $\xrightarrow{\text{dil. } NaOH} C_6H_5CH(OH)CH_2CHO$ $\xrightarrow{\Delta, -H_2O} C_6H_5CH=CHCHO$
$(ii)$ Benzyl alcohol is prepared from Benzene in two steps:
$1.$ Gattermann-Koch reaction of Benzene with $CO$ and $HCl$ in the presence of anhydrous $AlCl_3$ and $CuCl$ to form Benzaldehyde.
$2.$ Cannizzaro reaction of Benzaldehyde with concentrated $NaOH$ to form Benzyl alcohol and Sodium benzoate.
$C_6H_6$ $\xrightarrow{CO, HCl, \text{anhydrous } AlCl_3, CuCl} C_6H_5CHO$ $\xrightarrow{\text{conc. } NaOH, \Delta} C_6H_5CH_2OH + C_6H_5COONa$