Give equations of four lines passing through the point $(-2, 4)$.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
The general equation of a line passing through a point $(x_1, y_1)$ is given by $(y - y_1) = m(x - x_1)$,where $m$ is the slope.
For the point $(-2, 4)$,the equation is $(y - 4) = m(x + 2)$.
By choosing different values for the slope $m$,we can find infinitely many lines:
$1$. If $m = -1$,then $(y - 4) = -1(x + 2) \implies y - 4 = -x - 2 \implies x + y = 2$.
$2$. If $m = 1$,then $(y - 4) = 1(x + 2) \implies y - 4 = x + 2 \implies x - y = -6$.
$3$. If $m = -2$,then $(y - 4) = -2(x + 2) \implies y - 4 = -2x - 4 \implies 2x + y = 0$.
$4$. If $m = -0.5$,then $(y - 4) = -0.5(x + 2) \implies y - 4 = -0.5x - 1 \implies 0.5x + y = 3 \implies x + 2y = 6$.

Explore More

Similar Questions

The $y$-form of the equation $3x - 4y = 24$ is:

Determine the point on the graph of the linear equation $2x + 5y = 19$,whose ordinate is $1 \frac{1}{2}$ times its abscissa.

Find the value of $k$ if $(5, 2)$ is a solution of $3x + ky = 25$.

If the point $(3, 5)$ lies on the graph of the equation $ax + y = 20$,find the value of $a$.

Expressing $5x + 2y = 10$ in the $y$-form,we get.......

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo