Show the heterolytic and homolytic cleavage of $H_3C-Br$.

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(N/A) Heterolytic cleavage:
$H_3C-Br \rightarrow H_3C^+ + :Br^-$
In this process,the shared pair of electrons remains with the more electronegative atom $(Br)$,resulting in the formation of a carbocation $(H_3C^+)$ and a bromide ion $(:Br^-)$.
Homolytic cleavage:
$H_3C-Br \rightarrow H_3C^\bullet + ^\bullet Br$
In this process,each atom takes one electron from the shared pair,resulting in the formation of free radicals ($H_3C^\bullet$ and $^\bullet Br$).

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What is the fission of a covalent bond? Explain its types with examples and the main differences.

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In the above reaction,the electrophile is substituted at the meta position only,due to:
$I$. Electron density is more at ortho $\&$ para positions
$II$. Electron density is relatively less at ortho $\&$ para positions
$III$. Electron density is less at meta position
$IV$. Electron density is relatively more at meta position
The correct answer is:

Match the reactions in column $I$ with appropriate types of steps/reactive intermediate involved in these reactions as given in column $II$.
| Column $I$ | Column $II$ |
| :--- | :--- |
| $(A)$ $1-$phenylpentane$-1,4-$dione $\xrightarrow{aq. NaOH}$ $3-$phenylcyclopent$-2-$en$-1-$one | $(p)$ Nucleophilic substitution |
| $(B)$ $4-$chloro$-1-$phenylbutan$-1-$one $\xrightarrow{CH_3MgI}$ $2-$methyl$-2-$phenyltetrahydrofuran | $(q)$ Electrophilic substitution |
| $(C)$ $4-$hydroxy$-1-$phenylbutan$-1-$one $\xrightarrow{H_2SO_4}$ $2-$phenyl$-4,5-$dihydrofuran | $(r)$ Dehydration |
| $(D)$ $4-$methyl$-4-$phenylpentan$-1-$ol $\xrightarrow{H_2SO_4}$ $1,1-$dimethyl$-1,2,3,4-$tetrahydronaphthalene | $(s)$ Nucleophilic addition |
| | $(t)$ Carbanion |

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