Give the mechanism of chlorination of methane.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) The mechanism involves a chain reaction known as free radical substitution.
$1)$. Chain initiation: The reaction is initiated by $UV$ light,which breaks a chlorine molecule into two chlorine free radicals: $Cl_2 \xrightarrow{h\nu} 2Cl \cdot$
$2)$. Chain propagation: These steps keep the reaction going.
Step $A$: $CH_4 + Cl \cdot \rightarrow \cdot CH_3 + HCl$
Step $B$: $\cdot CH_3 + Cl_2 \rightarrow CH_3Cl + Cl \cdot$
$3)$. Chain termination: These reactions remove free radicals from the system.
$2Cl \cdot \rightarrow Cl_2$
$\cdot CH_3 + Cl \cdot \rightarrow CH_3Cl$
$\cdot CH_3 + \cdot CH_3 \rightarrow CH_3-CH_3$

Explore More

Similar Questions

How many isomeric vicinal-dihalides are possible for the compound having molecular formula $C_3H_6Cl_2$?

The compound $(X)$ on $(i)$ heating in the presence of anhydrous $AlCl_3$ and $HCl$ gas gives $2,4$-dimethylpentane, $(ii)$ aromatization gives toluene, and $(iii)$ cyclisation gives methylcyclohexane. The correct name of compound $(X)$ is:

Consider the following reaction:
$H_3C-CH(D)-CH(CH_3)-CH_3 + Br^\bullet \to X + HBr$
Identify the structure of the major product $X$.

Natural gas is a mixture of

Which of the following reactions is used to prepare hydrocarbons with an even number of carbon atoms?
$i.$ Wurtz reaction
$ii.$ Decarboxylation reaction
$iii.$ Kolbe's electrolysis
$iv.$ Reduction
$v.$ Hydrogenation

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo