Provide the orbital electronic configuration for the following elements: $Na, Mg, Al, Si, P, S, Cl, Ar, K, Ca$.

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Atom $(Z)$Orbital Electronic Configuration
$Na (11)$$[Ne] 3s^{1}$
$Mg (12)$$[Ne] 3s^{2}$
$Al (13)$$[Ne] 3s^{2} 3p_{x}^{1} 3p_{y}^{0} 3p_{z}^{0}$
$Si (14)$$[Ne] 3s^{2} 3p_{x}^{1} 3p_{y}^{1} 3p_{z}^{0}$
$P (15)$$[Ne] 3s^{2} 3p_{x}^{1} 3p_{y}^{1} 3p_{z}^{1}$
$S (16)$$[Ne] 3s^{2} 3p_{x}^{2} 3p_{y}^{1} 3p_{z}^{1}$
$Cl (17)$$[Ne] 3s^{2} 3p_{x}^{2} 3p_{y}^{2} 3p_{z}^{1}$
$Ar (18)$$[Ne] 3s^{2} 3p_{x}^{2} 3p_{y}^{2} 3p_{z}^{2}$
$K (19)$$[Ar] 4s^{1}$
$Ca (20)$$[Ar] 4s^{2}$

Note: $[Ne]$ represents $1s^{2} 2s^{2} 2p^{6}$ and $[Ar]$ represents $1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6}$.

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Similar Questions

The quantum numbers of six electrons are given below. Arrange them in order of increasing energy. If any of these combinations have the same energy,list them:
$(1)$ $n = 4, l = 2, m_l = 2, m_s = -1/2$
$(2)$ $n = 3, l = 2, m_l = 1, m_s = +1/2$
$(3)$ $n = 4, l = 1, m_l = 0, m_s = +1/2$
$(4)$ $n = 3, l = 2, m_l = -2, m_s = -1/2$
$(5)$ $n = 3, l = 1, m_l = -1, m_s = +1/2$
$(6)$ $n = 4, l = 1, m_l = 0, m_s = +1/2$

The maximum number of electrons present in the $N$ shell is:

Which of the following statements concerning the four quantum numbers is false?

Which of the following are correct?
$(1)$ Electron density in $XY$ plane for $d_{x^2-y^2}$ orbital is zero.
$(2)$ The energy of $3p$-orbital is higher than the energy of $2p$-orbital.
$(3)$ $3p_z$-orbital has one angular node.
$(4)$ $4f$-orbital has no radial node.

Which of the following electronic configurations has the maximum energy?

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