Give the CGS unit of universal gravitational | vedclass

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(A) According to Newton's law of universal gravitation,the force $F$ between two masses $m_1$ and $m_2$ separated by a distance $r$ is given by $F = G

Vedclass · Accepted Answer

$dyn \cdot cm^2 \cdot g^{-2}$

Vedclass · Answer

(A) According to Newton's law of universal gravitation,the force $F$ between two masses $m_1$ and $m_2$ separated by a distance $r$ is given by $F = G \frac{m_1 m_2}{r^2}$.Rearranging for $G$,we get $G = \frac{F \cdot r^2}{m_1 \cdot m_2}$.In the $CGS$ system,the unit of force $F$ is $dyne$ $(dyn)$,the unit of distance $r$ is $centimeter$ $(cm)$,and the unit of mass $m$ is $gram$ $(g)$.Substituting these units into the formula for $G$,we get the unit of $G = \frac{dyn \cdot cm^2}{g \cdot g} = dyn \cdot cm^2 \cdot g^{-2}$.

Give the $CGS$ unit of universal gravitational constant $(G)$.

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