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(B) The reaction sequence proceeds as follows:$1$. Nitration of benzene with $HNO_3/H_2SO_4$ gives nitrobenzene $(C_6H_5NO_2)$.$2$. Reduction of nitro

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$C_6H_5COCH_3$

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(B) The reaction sequence proceeds as follows:$1$. Nitration of benzene with $HNO_3/H_2SO_4$ gives nitrobenzene $(C_6H_5NO_2)$.$2$. Reduction of nitrobenzene with $H_2/Pd/C$ gives aniline $(C_6H_5NH_2)$.$3$. Diazotization of aniline with $NaNO_2/HCl$ at $0-5^{\circ}C$ gives benzenediazonium chloride $(C_6H_5N_2^+Cl^-)$.$4$. Reaction with $CuCN$ (Sandmeyer reaction) replaces the diazonium group with a cyano group,yielding benzonitrile $(C_6H_5CN)$.$5$. Grignard reaction with $MeMgBr$ followed by acidic hydrolysis $(H_3O^+)$ converts the nitrile group into a ketone group,yielding acetophenone $(C_6H_5COCH_3)$.

Give the product of the following reaction sequence:

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