Give the product of the following reaction se | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The reaction sequence is as follows:$1$. Nitration of benzene with $HNO_3/H_2SO_4$ gives nitrobenzene.$2$. Bromination of nitrobenzene with $Br_2/

Vedclass · Accepted Answer

$4-$bromo$-1-$chloro$-2-$iodobenzene

Vedclass · Answer

(C) The reaction sequence is as follows:$1$. Nitration of benzene with $HNO_3/H_2SO_4$ gives nitrobenzene.$2$. Bromination of nitrobenzene with $Br_2/FeBr_3$ gives $m$-bromonitrobenzene because the $-NO_2$ group is meta-directing.$3$. Reduction of $m$-bromonitrobenzene with $H_2/Pd/C$ gives $m$-bromoaniline.$4$. Chlorination of $m$-bromoaniline with $Cl_2/FeBr_3$ gives $2$-chloro-$5$-bromoaniline (the $-NH_2$ group is strongly ortho/para directing,and the para position is occupied by $-Br$,so it directs to the ortho position).$5$. Diazotization with $NaNO_2/HCl$ converts the $-NH_2$ group to a diazonium salt $(-N_2^+Cl^-)$.$6$. Treatment with $KI$ replaces the diazonium group with an iodine atom,resulting in $1$-chloro-$2$-iodo-$4$-bromobenzene (or $4$-bromo-$1$-chloro-$2$-iodobenzene).

Give the product of the following reaction sequence:

Similar Questions

Which of the following has the maximum boiling point?

In the following substitution reaction $:$
Product $P$ formed is $:$

$CH \equiv CH$ $\xrightarrow{\text{Red Hot Fe tube}} A$ $\xrightarrow[\text{Dark}]{Cl_2 / FeCl_3} B$ $\xrightarrow[\text{Anhy. } AlCl_3]{CH_3 - Cl} C$ (Major)
Product '$C$' is

$m$-Bromoanisole reacts with $NaNH_2$ in liquid $NH_3$ to give mainly:

Write the nucleophilic substitution reactions of $Cl^-$ in $C-Cl$ bond of haloarenes with $OH^-$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module