Given n(U) = 20,n(A) = 12,n(B) = 9,n(A cap B) | vedclass

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(D) First,we find the number of elements in the union of sets $A$ and $B$ using the formula:$n(A \cup B) = n(A) + n(B) - n(A \cap B)$$n(A \cup B) = 12

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$3$

Vedclass · Answer

(D) First,we find the number of elements in the union of sets $A$ and $B$ using the formula:$n(A \cup B) = n(A) + n(B) - n(A \cap B)$$n(A \cup B) = 12 + 9 - 4 = 17$Now,we find the number of elements in the complement of $(A \cup B)$ using the universal set $U$:$n((A \cup B)^C) = n(U) - n(A \cup B)$$n((A \cup B)^C) = 20 - 17 = 3$Therefore,the correct option is $D$.

Given $n(U) = 20$,$n(A) = 12$,$n(B) = 9$,$n(A \cap B) = 4$,where $U$ is the universal set,$A$ and $B$ are subsets of $U$,then $n((A \cup B)^C) = $

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