Given A = {1, 2, 3, 4, 5} and B = {1, 4, 5}. | vedclass

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(A) The relation $R$ is defined from $A$ to $B$ as $R = \{(x, y) : x \in A, y \in B, x > y\}$.We check each element $x \in A$ against $y \in B$ where

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$\{1, 4\}$

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(A) The relation $R$ is defined from $A$ to $B$ as $R = \{(x, y) : x \in A, y \in B, x > y\}$.We check each element $x \in A$ against $y \in B$ where $x > y$:For $x = 2$,$y = 1$ $(2 > 1)$,so $(2, 1) \in R$.For $x = 3$,$y = 1$ $(3 > 1)$,so $(3, 1) \in R$.For $x = 4$,$y = 1$ $(4 > 1)$ and $y = 1$ is not the only one,$y = 1$ is valid. Also $4 > 1$,so $(4, 1) \in R$.For $x = 5$,$y = 1$ $(5 > 1)$ and $y = 4$ $(5 > 4)$,so $(5, 1) \in R$ and $(5, 4) \in R$.The set of all ordered pairs in $R$ is $\{(2, 1), (3, 1), (4, 1), (5, 1), (5, 4)\}$.The range is the set of all second elements in the ordered pairs of $R$.Range $R = \{1, 4\}$.

Given $A = \{1, 2, 3, 4, 5\}$ and $B = \{1, 4, 5\}$. If $R$ is a relation from $A$ to $B$ such that $(x, y) \in R$ with $x > y$,then the range of $R$ is:

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