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(B) According to the Ellingham diagram,the line for the formation of $MgO$ $(2Mg   O_{2} \rightarrow 2MgO)$ intersects the line for the formation of $

Vedclass · Accepted Answer

Both $A$ and $R$ are correct,but $R$ is $NOT$ the correct explanation of $A$.

Vedclass · Answer

(B) According to the Ellingham diagram,the line for the formation of $MgO$ $(2Mg   O_{2} \rightarrow 2MgO)$ intersects the line for the formation of $Al_{2}O_{3}$ $(4/3 Al   O_{2} \rightarrow 2/3 Al_{2}O_{3})$ at $1350^{\circ} C$.Below $1350^{\circ} C$,the $MgO$ line lies below the $Al_{2}O_{3}$ line,meaning $Mg$ is a better reducing agent and can reduce $Al_{2}O_{3}$.Above $1350^{\circ} C$,the $Al_{2}O_{3}$ line lies below the $MgO$ line,meaning $Al$ is a better reducing agent and can reduce $MgO$. Thus,Assertion $A$ is correct.Reason $R$ states that the melting and boiling points of magnesium are lower than those of aluminium. While this is a factual statement,it is not the reason for the intersection of the Ellingham lines,which depends on the standard Gibbs free energy of formation $(\Delta G^{\circ})$ of the oxides. Thus,$R$ is correct but is not the correct explanation of $A$.

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