Given below are the quantum numbers for 4 ele | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The energy of an orbital is determined by the $(n + l)$ rule.$A$ $\Rightarrow 3d$ $\Rightarrow n + l = 3 + 2 = 5$$B$ $\Rightarrow 4p$ $\Rightarrow

Vedclass · Accepted Answer

$D < A < B < C$

Vedclass · Answer

(B) The energy of an orbital is determined by the $(n + l)$ rule.$A$ $\Rightarrow 3d$ $\Rightarrow n + l = 3 + 2 = 5$$B$ $\Rightarrow 4p$ $\Rightarrow n + l = 4 + 1 = 5$$C$ $\Rightarrow 4d$ $\Rightarrow n + l = 4 + 2 = 6$$D$ $\Rightarrow 3p$ $\Rightarrow n + l = 3 + 1 = 4$According to the $(n + l)$ rule,the energy increases as the $(n + l)$ value increases.If the $(n + l)$ values are the same,the orbital with the lower $n$ value has lower energy.Comparing the values:$D (n+l = 4) Therefore,the correct order of increasing energy is $D < A < B < C$.

Given below are the quantum numbers for $4$ electrons.
$A. \; n = 3, l = 2, m_l = 1, m_s = +1/2$
$B. \; n = 4, l = 1, m_l = 0, m_s = +1/2$
$C. \; n = 4, l = 2, m_l = -2, m_s = -1/2$
$D. \; n = 3, l = 1, m_l = -1, m_s = +1/2$
The correct order of increasing energy is

Similar Questions

When the azimuthal quantum number has a value of $l = 1$,the shape of the orbital is

The orbital angular momentum of an electron in an $s$ orbital is:

Show the distribution of electrons in an oxygen atom (atomic number $8$) using an orbital diagram.

If the Aufbau principle had not been followed,$Ca$ $(Z = 20)$ would have been placed in the

What is the number of orbitals in any subshell? Explain.

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Given below are the quantum numbers for $4$ electrons.$A. \; n = 3, l = 2, m_l = 1, m_s = +1/2$$B. \; n = 4, l = 1, m_l = 0, m_s = +1/2$$C. \; n = 4, l = 2, m_l = -2, m_s = -1/2$$D. \; n = 3, l = 1, m_l = -1, m_s = +1/2$The correct order of increasing energy is