Given below are the statements about diborane | vedclass

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Question

(C) Statement $(a)$ is correct: Diborane is prepared by the reaction of $NaBH_{4}$ with $I_{2}$ as follows: $2 NaBH_{4} + I_{2} \rightarrow B_{2}H_{6}

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$(a)$ only

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(C) Statement $(a)$ is correct: Diborane is prepared by the reaction of $NaBH_{4}$ with $I_{2}$ as follows: $2 NaBH_{4} + I_{2} \rightarrow B_{2}H_{6} + 2 NaI + H_{2}$.Statement $(b)$ is incorrect: In diborane,each boron atom is $sp^{3}$ hybridized.Statement $(c)$ is incorrect: Diborane has two bridged $3$ centre$-2$ electron $(3c-2e^-)$ bonds,not one.Statement $(d)$ is incorrect: Diborane is a non-planar molecule.Therefore,only statement $(a)$ is correct.

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