Given below are two statements for the follow | vedclass

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(B) $1$. Compound $'X'$ $(C_3H_6Cl_2)$ reacts with excess $NaNH_2$ to form propyne $(CH_3-C \equiv CH)$ as compound $'Y'$. $2$. Hydration of propyne $

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Both Statement $I$ and Statement $II$ are true

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(B) $1$. Compound $'X'$ $(C_3H_6Cl_2)$ reacts with excess $NaNH_2$ to form propyne $(CH_3-C \equiv CH)$ as compound $'Y'$. $2$. Hydration of propyne $(Y)$ with $dil. H_2SO_4/Hg^{2+}$ gives acetone $(CH_3-CO-CH_3)$ as compound $'Z'$. Acetone contains a methyl ketone group and gives a yellow precipitate of iodoform $(CHI_3)$ with $NaOI$. Thus, Statement $I$ is true. $3$. Cyclic trimerization of propyne $(Y)$ using a red hot iron tube gives $1,3,5$-trimethylbenzene (mesitylene) as compound $'Q'$ $(C_9H_{12})$. $4$. In $1,3,5$-trimethylbenzene, there are $3$ aromatic $H$ atoms (on the ring) and $9$ aliphatic $H$ atoms (in the three methyl groups). The ratio of aromatic to aliphatic $H$ atoms is $3:9 = 1:3$. Thus, Statement $II$ is true.

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