Given below are two statements.Statement I : | vedclass

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(C) Step $1$: Analyze Statement $I$. In $H_2O_2$ (hydrogen peroxide), oxygen is in the peroxide state, so its oxidation number is $-1$. In $RbO_2$ (ru

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Statement $I$ is correct but statement $II$ is incorrect

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(C) Step $1$: Analyze Statement $I$. In $H_2O_2$ (hydrogen peroxide), oxygen is in the peroxide state, so its oxidation number is $-1$. In $RbO_2$ (rubidium superoxide), oxygen is in the superoxide state, so its oxidation number is $-\frac{1}{2}$. Thus, Statement $I$ is correct.Step $2$: Analyze Statement $II$. In $HAuCl_4$, the oxidation state of $Au$ is $+3$, so it is represented as $HAu(III)Cl_4$. In $MnO_2$, the oxidation state of $Mn$ is $+4$ (since $x + 2(-2) = 0 \implies x = +4$), so it should be represented as $Mn(IV)O_2$. The statement claims $Mn(II)O_2$, which is incorrect. Thus, Statement $II$ is incorrect.

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