Given below are two statements: Statement $I$: The condensation reaction between $CH_{3} - CH = O$ and $H_{2}N - NH - C(=O) - NH_{2}$ under optimum pH will produce $CH_{3} - CH = N - N(H) - C(=O) - NH_{2}$. Statement $II$: The molecule, $Ph - CH(OH)(OCH_{3})$ will generate $Ph - CH = O$ in the presence of dilute acid. In the light of the above statements, choose the correct answer from the options given below:

  • A
    Both Statement $I$ and Statement $II$ are true
  • B
    Both Statement $I$ and Statement $II$ are false
  • C
    Statement $I$ is true but Statement $II$ is false
  • D
    Statement $I$ is false but Statement $II$ is true

Explore More

Similar Questions

$CH_3CH=CHCHO$ is oxidized to $CH_3CH=CHCOOH$ using

Identify the product for the following reaction: $CH_3-CO-CH_3 + HO-CH_2-CH_2-OH \xrightarrow{HCl} ?$

Predict the major product of the following reaction sequence:

Explain aldol condensation and the acidity of the $\alpha$-carbon of aldehydes and ketones. Provide the aldol condensation reactions for $ethanal$ and $propanone$.

Difficult
View Solution

$A$ carbonyl compound $X$ $(C_8H_8O)$ undergoes disproportionation with conc. $KOH$ on heating. The product of $X$ with $Zn-Hg/HCl$ is $Y$ and the product of $X$ with $NaBH_4$ is $Z$. What are $Y$ and $Z$ respectively?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo