Given below are two statements:Statement I: [ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Statement $I$:$1.$ $[Mn(CN)_6]^{3-}: Mn^{3+} = [Ar] 3d^4$. $CN^{-}$ is a strong field ligand. Configuration: $t_{2g}^4 e_g^0$. Hybridization: $d^2

Vedclass · Accepted Answer

Both statement $I$ and statement $II$ are true

Vedclass · Answer

(D) Statement $I$:$1.$ $[Mn(CN)_6]^{3-}: Mn^{3+} = [Ar] 3d^4$. $CN^{-}$ is a strong field ligand. Configuration: $t_{2g}^4 e_g^0$. Hybridization: $d^2sp^3$.$2.$ $[Fe(CN)_6]^{3-}: Fe^{3+} = [Ar] 3d^5$. $CN^{-}$ is a strong field ligand. Configuration: $t_{2g}^5 e_g^0$. Hybridization: $d^2sp^3$.$3.$ $[Co(C_2O_4)_3]^{3-}: Co^{3+} = [Ar] 3d^6$. $C_2O_4^{2-}$ is a strong field ligand for $Co^{3+}$. Configuration: $t_{2g}^6 e_g^0$. Hybridization: $d^2sp^3$.Statement $I$ is correct.Statement $II$:$1.$ $[MnCl_6]^{3-}: Mn^{3+} = [Ar] 3d^4$. $Cl^{-}$ is a weak field ligand. Configuration: $t_{2g}^3 e_g^1$. Unpaired electrons = $4$. Paramagnetic.$2.$ $[FeF_6]^{3-}: Fe^{3+} = [Ar] 3d^5$. $F^{-}$ is a weak field ligand. Configuration: $t_{2g}^3 e_g^2$. Unpaired electrons = $5$. Paramagnetic.Statement $II$ is correct.

Similar Questions

The geometries of some complex ions are given below. Select the correct answer.
$(1) [Ag(NH_3)_2]^+ - \text{Linear}$
$(2) [MnCl_4]^{2-} - \text{Tetrahedral}$
$(3) [Cu(NH_3)_4]^{2+} - \text{Square planar}$
$(4) [Ni(CN)_4]^{2-} - \text{Square planar}$

Which of the following complexes exhibits square planar geometry?

What is the type of hybridization of $Ag$ in the linear complex $[Ag(NH_3)_2]^+$?

Which of the following complexes does not exhibit $d^2sp^3$ hybridization?

Considering that $\Delta_{0} > P$,the magnetic moment (in $BM$) of $[Ru(H_{2}O)_{6}]^{2+}$ would be

Vedclass Test Series

Exam Paper Generator

Online Exam Module