Given below are two statements:
Statement $I$: $(CH_3)_3C-CH_2-Cl$ will undergo $S_N1$ reaction even though it is a primary halide.
Statement $II$: It will not undergo $S_N2$ reaction very easily even though it is a primary halide.
In the light of the above statements,choose the most appropriate answer from the options given below:

  • A
    Statement $I$ is incorrect but Statement $II$ is correct.
  • B
    Both Statement $I$ and Statement $II$ are incorrect.
  • C
    Statement $I$ is correct but Statement $II$ is incorrect.
  • D
    Both Statement $I$ and Statement $II$ are correct.

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Select the incorrect option:

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What is the correct order of leaving group ability for the following groups?
$I. -OAc$
$II. -OMe$
$III. -OSO_2Me$
$IV. -OSO_2CF_3$

Match the $LIST$-$I$ with $LIST$-$II$:
List-$I$ (Reaction)List-$II$ (Mechanism)
$A$. Williamson Synthesis$I$. Electrophilic addition
$B$. Friedel-Crafts Reaction$II$. Free radical substitution
$C$. Bromination of vinyl benzene$III$. Nucleophilic substitution
$D$. Chlorination of toluene in light$IV$. Electrophilic substitution

Choose the correct answer from the options given below:

Identify the product obtained in the following reaction: $CH_3CH_2Br + CH_3COOAg \xrightarrow{\Delta} x + AgBr$

The graph which represents the following reaction is :
$(C_6H_5)_3C-Cl \xrightarrow{OH^{-} / \text{Pyridine}} (C_6H_5)_3C-OH$

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