Given below are two statements:Statement I: T | vedclass

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(C) Statement $I$: Ions with $d^0$ or $d^{10}$ configuration are colourless. $Sc^{3+}$ $(d^0)$, $Ti^{4+}$ $(d^0)$, and $Zn^{2+}$ $(d^{10})$ are colour

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Both Statement $I$ and Statement $II$ are false

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(C) Statement $I$: Ions with $d^0$ or $d^{10}$ configuration are colourless. $Sc^{3+}$ $(d^0)$, $Ti^{4+}$ $(d^0)$, and $Zn^{2+}$ $(d^{10})$ are colourless. - $[Sc^{3+}, Ti^{3+}]$: $Sc^{3+}$ is colourless, $Ti^{3+}$ is coloured. - $[Mn^{2+}, Cr^{2+}]$: Both are coloured ($Mn^{2+}$ is $d^5$, $Cr^{2+}$ is $d^4$). - $[Cu^{2+}, Zn^{2+}]$: $Cu^{2+}$ is coloured $(d^9)$, $Zn^{2+}$ is colourless. - $[Ni^{2+}, Ti^{4+}]$: $Ni^{2+}$ is coloured $(d^8)$, $Ti^{4+}$ is colourless. Only $1$ pair $([Mn^{2+}, Cr^{2+}])$ has both ions coloured. Thus, Statement $I$ is false. Statement $II$: $Th^{4+}$ is the most stable oxidation state of Thorium and cannot be oxidized further, so it cannot act as a reducing agent. $Eu^{2+}$ is a strong reducing agent as it tends to change to $Eu^{3+}$. Thus, Statement $II$ is false.

Property	Metal
$a$. Element with highest second ionization enthalpy $(\Delta_{i} H_2)$	$i$. $Co$
$b$. Element with highest third ionization enthalpy $(\Delta_{i} H_3)$	$ii$. $Cr$
$c$. $M$ in $[M(CO)_6]$	$iii$. $Cu$
$d$. Element with highest heat of atomization $(\Delta_{a} H)$	$iv$. $Zn$
	$v$. $Ni$

Column-$I$	Column-$II$
$(1)$ General electronic configuration of $d$-block elements	$(A)$ Transition elements
$(2)$ $d$-block elements	$(B)$ $(n-1)d^{1-10}ns^{1-2}$
$(3)$ Groups $3$ to $12$	$(C)$ $Z = 58$ to $71$
$(4)$ Lanthanoid elements	$(D)$ Last electron enters $d$-orbital

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