Given below are two statements:Statement I: T | vedclass

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(A) Statement $I$: $Ti^{4+}$ $(d^0)$ is colourless due to the absence of unpaired electrons. $V^{2+}$ $(d^3)$, $Mn^{2+}$ $(d^5)$, $Fe^{3+}$ $(d^5)$, a

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Both Statement $I$ and Statement $II$ are correct

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(A) Statement $I$: $Ti^{4+}$ $(d^0)$ is colourless due to the absence of unpaired electrons. $V^{2+}$ $(d^3)$, $Mn^{2+}$ $(d^5)$, $Fe^{3+}$ $(d^5)$, and $Cr^{2+}$ $(d^4)$ all have unpaired electrons and are coloured.The pairs where both ions are coloured are: $[V^{2+}, Mn^{2+}]$, $[Mn^{2+}, Fe^{3+}]$, and $[V^{2+}, Cr^{2+}]$.Thus, the count is $3$. Statement $I$ is correct.Statement $II$: $La^{3+}$ $(f^0)$, $Lu^{3+}$ $(f^{14})$, $Ac^{3+}$ $(f^0)$, and $Lr^{3+}$ $(f^{14})$ are diamagnetic. $Yb^{2+}$ $(f^{14})$ and $Ce^{4+}$ $(f^0)$ are also diamagnetic.The pairs where both ions are diamagnetic are: $[La^{3+}, Yb^{2+}]$, $[Lu^{3+}, Ce^{4+}]$, and $[Ac^{3+}, Lr^{3+}]$.Thus, the count is $3$. Statement $II$ is correct.

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